I have two IPv6s on an iface: 2001:41e0:ff3a::1/128 and 2001:41e0:ff00:82::2/64 (the former being a sixxs.net subet, the latter a tunnel subnet). Since the /128 is added last (and more specific), it gets used for outgoing packets, except for when I access hosts that have a longer common prefix, such as 2001:41e0:ff3d::1, which has a longer common prefix with 2001:41e0:ff3a::1 than 2001:41e0:ff00:82::2. This is according to RFC 3484 and documented nicely here: http://linux-hacks.blogspot.com/2008/07/default-address-selection-part-2.html Obviously, I don't want to use my tunnel subnet IP, but instead the one from the /48 subnet I was assigned. I am thus trying to force the use of 2001:41e0:ff3a::1 for all outgoing packets, so I ran ip -6 r a default via 2001:41e0:ff00:82::1 dev sixxs src 2001:41e0:ff3a::1 but the src argument seems to get ignored and doesn't show up in a subsequent `ip route list`. Do I really have to use `ip rule`s? (`ip addrlabel` is not available on this box yes)? How would such a rule look like? I understand `ip rule`s to shove packets into specific routing tables, where something like a default route would then route them on, and thus I doubt that the `src` argument would work here. FWIW, this is not the issue discussed at http://www.sixxs.net/forum/?msg=setup-574428, which is when you have two default routes and need to route response packets out the one where the request came from.